The canonical sequence is:
Rance -> FT -> shuffle -> FT -> shuffle -> FT
This is the result:
The following sequence also arrives there:
FT -> Rance -> shuffle -> FT -> shuffle -> FT
which proves the commutability between FT and Rance. When I try this:
FT -> shuffle -> FT -> Rance -> shuffle -> FT
the result is:
No comments:
Post a Comment